24x^2-38x-7=0

Solution for 24x^2-38x-7=0 equation:

24x^2-38x-7=0

a = 24; b = -38; c = -7;
Δ = b2-4ac
Δ = -382-4·24·(-7)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-46}{2*24}=\frac{-8}{48}
=-1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+46}{2*24}=\frac{84}{48}
=1+3/4
$